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^2+3Z^2=180
We move all terms to the left:
^2+3Z^2-(180)=0
determiningTheFunctionDomain 3Z^2-180+^2=0
We add all the numbers together, and all the variables
3Z^2=0
a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$Z=\frac{-b}{2a}=\frac{0}{6}=0$
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